Practice Hand 3 · Defense · Deal 15 from Chapter 26

Rule of 11 on Defense

Subtract the card led from 11 — and find declarer's cards.

North · Dummy

K 10 4
Q 9 3
A 8 5
J 10 5 2

10 HCP

East · You (Defender)

A J 7
K 8 5 2
10 7 4
Q 8 3

10 HCP

Contract: 3NT by West (declarer)
Opening Lead: South (your partner) leads 6. Dummy plays 4.
The Bidding:
WestNorthEastSouth
1NTPass3NTPass
PassPass
Your task: Your partner leads 6 against 3NT. Dummy plays 4. Which card should you (East) play, and why?

Solution

Apply the Rule of 11

Subtract the card led from 11: 11 − 6 = 5. That's how many cards higher than the 6 sit in the three other hands combined.

Count what you can see

Dummy has K and 10 — 2 higher. You hold A, J, 7 — 3 higher. 2 + 3 = 5. That accounts for all five.

The math is decisive: declarer (West) has zero spades higher than the 6.

Play the 7

Not the Ace. Not the Jack. The 7 wins the trick because declarer cannot beat it. More importantly, your AJ stay in place as a tenace over dummy's K10.

When you regain the lead later, lead a spade through dummy. Whatever dummy plays, your AJ catches it — and partner's spade suit becomes established. Playing the Ace or Jack now would waste the tenace and let dummy's K become a winner.

Key point: The Rule of 11 only works when partner leads fourth-best, but most leads against notrump are exactly that. Used here, it tells you with certainty that declarer holds nothing higher — so you can hold your tenace and destroy declarer's communications.

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